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I am studying my 2330...the maths is bogging me down a little but i think i am getting it...when all of a sudden bang...self doubt.So i wondered if any of the sparkys on here or trainees may be able to help.

It is a question at the beggining of the practical about the 2 way lighting circuit......

The circuit is 24v with two 40 w bulbs...the questions are

Note the power rating of all loads on the circuit...well all i can think of is

p=v x i

or is this to do with the testing of the circuit that i have not done yet.

It then goes on calculate the resistance of the circuit...so are the 40 watt lamps resistors...i suppose they are but to convert watts to amps

I=watts divided by voltage
So 80w/24v is 3.33amps

ohms law then makes

the resistance 7.05 ohms.

Does this sound right!!Any help advice greatly and humbly recieved.:D
 

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Note the power rating of all loads on the circuit...well all i can think of is

p=v x i

or is this to do with the testing of the circuit that i have not done yet.

It then goes on calculate the resistance of the circuit...so are the 40 watt lamps resistors...i suppose they are but to convert watts to amps

I=watts divided by voltage
So 80w/24v is 3.33amps

ohms law then makes

the resistance 7.05 ohms.

Does this sound right!!Any help advice greatly and humbly recieved.:D
Power is measured in watts, and surely the only two loads on the circuit are the 2 40w bulbs, so isnt that the answer?

As for the resistance

V=IR
so R=V/I

You dont know I, but P=IV so I=P/V

so R=V/P/V

so R=V(squared)/P

I THINK thats right... i do A level physics and as far i can remember and tell, this makes sense to me...
 
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